The Nameless Blog

The integers from 1 to n are stored in an array in a random
fashion. but one integer is missing. write a program to find the
missing integer.
   ans. idea. the sum of n natural numbers is = n(n+1)/2.
        if we subtract the above sum from the sum of all the
        numbers in the array , the result is nothing but the
        missing number.

typedef struct{
 char *;
 nodeptr next;
 } * nodeptr;
what does nodeptr stand for?

int   *x[](); means
expl: Elments of an array can't be functions.

o/p=?
int i;
i=1;
i=i+2*i++;
printf(%d,i);
                    ans: 4

#include
char *f()
{char *s=malloc(8);
strcpy(s,"goodbye")}
main()
{
char *f();
printf("%c",*f()='A');
o/p=?

FILE *fp1,*fp2;
fp1=fopen("one","w")
fp2=fopen("one","w")
fputc('A',fp1)
fputc('B',fp2)
fclose(fp1)
fclose(fp2)}
ans: no error. But It will over writes on same
file.

#define MAN(x,y) (x)>(y)?(x):(y)
{  int i=10;j=5;k=0;
k= MAX(i++,++j)
printf(%d %d %d %d,i,j,k)}

a=10;b=5; c=3;d=3;
if(a

what is o/p
>   #include
>   show(int t,va_list ptr1)
>   {
>   int a,x,i;
>   a=va_arg(ptr1,int)
>   printf("\n %d",a)
>   }
>   display(char)
>   {int x;
>   listptr;
>   va_star(otr,s);
>   n=va_arg(ptr,int);
>   show(x,ptr);
>   }
>   main()
>   {
>   display("hello",4,12,13,14,44);
>   }
>   a) 13 b) 12 c) 44 d) 14

main()
> {
> printf("hello");
> fork();
> }

main()
> {
> int i = 10;
> printf(" %d %d %d \n", ++i, i++, ++i);
> }

#include
> main()
> {
> int *p, *c, i;
> i = 5;
> p = (int*) (malloc(sizeof(i)));
> printf("\n%d",*p);
> *p = 10;
> printf("\n%d  %d",i,*p);
> c = (int*) calloc(2);
> printf("\n%d\n",*c);
> }

#define MAX(x,y) (x) >(y)?(x):(y)
> main()
> {
>  int i=10,j=5,k=0;
>   k=  MAX(i++,++j);
>    printf("%d..%d..%d",i,j,k);
>  }

#include 
> main()
> {
>         enum _tag{ left=10, right, front=100, back};
>         printf("left is %d, right is %d, front is
> %d, back is
> %d",left,right,front,back);
> }

main()
> {
>         int a=10,b=20;
>  a>=5?b=100:b=200;
>         printf("%d\n",b);
> }

#define PRINT(int) printf("int = %d  ",int)
> main()
> {
> int x,y,z;
> x=03;y=02;z=01;
> PRINT(x^x);
> z<<=3;PRINT(x); > y>>=3;PRINT(y);
> }

what is the o/p of the program
main()
{
 int rows=3,colums=4;
 int a[rows][colums]={1,2,3,4,5,6,7,8,9,10,11,12};
   i=j=k=99;
   for(i=0;i

what is o/p
main()
{int i=3;
while(i--)
{
int i=100
i--;
printf("%d..",i);
}
}
a) infinite loop
b) error
c) 99..99..99..99
d) 3..22..1..

'-'=45  '/'=47
printfr(%d/n,'-','-','-','-','/','/','/');
o/p =?

{ ch='A';
while(ch<='F'){   switch(ch){   case'A':case'B':case'C':case'D':ch++;continue;   case'E':case'F':ch++;   }   putchar(ch);   }   }     a)ABCDEF  b.EFG c.FG d.error