DRDO :: Placement Paper - I
Posted by Subash | 9:23 PM
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- Which is the fastest Cruise Missile?
- What is Wi Fi?
- The New Biotechnology Software intorduced by TCS is?
- Which country is not a Member of SAARC
a) Bangladesh
b) Myanmar
c) Maldives
d) Nepal - Laser is used for what?
a) Treatment of Cancer
b) Treatment of Eyes
c) Treatment of Heart
d) Treatment of Kidney - In Which Day world Telecom Day Celebrated?
- The area of red planet where the Mars Rover Landed?
- Find values for a,b,c,d
c 1 1 1
0 a 1 b
_______
1 0 d 0
The minumum no. of Multiplications needed to compute x^768 is
a) 9
b) 10
c) 425
d) 767- What is Interface Control Information?
- In a switch the mean arrival rate of packets is 800 Packets/sec and the the mean service
rate is 925 Packets/sec
a) .008 Sec
b) .08 sec
c) .8 sec
d) 1.1 sec - Average No. of Comparisons required to sort 3 elements is
a) 2
b) 2.33
c) 2.67
d) 3 - The internal path length of a Bonary Tree with 10nodes is 25. The external path length is
a) 25
b) 35
c) 40
d) 45 - The minumum number of comparisons requied to find the second smallest element in a
1000 element array is
a) 1008
b) 1010
c) 1999
d) 2000 - Suppose all elements above the principal diagonal od n x n matix A are zero. If non zero
elements of the lower triangular Matrix is stored in an array B with A[1][1] stored at
B[1]. The addressing formula to the nonzero element in A[i][j]=?
a) A[i][j]
b) i(j-1)/2 +i
c) j(i-1)/2 +i
d) i(i-1)/2 +j - A harddisk has a rotation speed of 4500RPM. then the latency time is
a) .4
b) .6
c) .7
d) .9 - Average transfer speed of a i/p serial line is minimum 25,000 Bytes & maximum 60000
Bytes. Polling Strategy adopted takes 4microsec(whether there is any i/p byte or not). It is assured that byte that retrived from controller before next byte arrives are lost. Then the maximum safe polling interveal is
a) 12
b) 12.33
c) 12.67
d) 32 - Assume a system has 16MB cache mean Disk Access Time & cache Access time is 76.5
ns & 1.5 overall mean Access time us 465ms for each tripling the memory the miss rate is
halved. The memory required to bring down the mean Access time to 24ns is
a) 16 MB
b) 24 MB
c) 32 MB
d) 48 MB - The no. of edjes in disjoint Hamilton circuit in a complex graph with 17 edges is
a) 8
b) 9
c) 136
d) 17^2 - If 100ns is Memory Access Time & 125 microsec is 1frame period. The no. of line that
can be supported in a Time Divison Switch is
a)125 Lines
b)625 Lines
c)525 Lines
d)465 Lines